Find the remainder when x^{3}+3x^{2}+3x+1 is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $p(x) = x^{3} + 3x^{2} + 3x + 1$.According to the Remainder Theorem,when a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.H

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) Let $p(x) = x^{3} + 3x^{2} + 3x + 1$.According to the Remainder Theorem,when a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,we are dividing by $x$,which is equivalent to $(x - 0)$. Thus,$a = 0$.To find the remainder,we calculate $p(0)$:$p(0) = (0)^{3} + 3(0)^{2} + 3(0) + 1$$p(0) = 0 + 0 + 0 + 1 = 1$.Therefore,the remainder is $1$.

Find the remainder when $x^{3}+3x^{2}+3x+1$ is divided by $x$.

Similar Questions

Verify whether the following are zeroes of the polynomial indicated against them:
$p(x) = (x + 1)(x - 2)$,$x = -1, 2$

Write the following cube in expanded form: $\left[\frac{3}{2} x+1\right]^{3}$

Examine whether $x+2$ is a factor of $x^{3}+3x^{2}+5x+6$ and of $2x+4$.

Use the Factor Theorem to determine whether $g(x)$ is a factor of $p(x)$ in each of the following cases: $p(x) = 2x^3 + x^2 - 2x - 1$,$g(x) = x + 1$.

Factorise: $\frac{25}{4} x^{2}-\frac{y^{2}}{9}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module